x=-0.016x^2+0.9x+6

Solution for x=-0.016x^2+0.9x+6 equation:

x=-0.016x^2+0.9x+6

We move all terms to the left:

x-(-0.016x^2+0.9x+6)=0

We get rid of parentheses

0.016x^2-0.9x+x-6=0

We add all the numbers together, and all the variables

0.016x^2+0.1x-6=0

a = 0.016; b = 0.1; c = -6;
Δ = b2-4ac
Δ = 0.12-4·0.016·(-6)
Δ = 0.394
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.1)-\sqrt{0.394}}{2*0.016}=\frac{-0.1-\sqrt{0.394}}{0.032}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.1)+\sqrt{0.394}}{2*0.016}=\frac{-0.1+\sqrt{0.394}}{0.032}
$